Assuming no involvement of the bombay phenotype: a. if e girl has blood type o, whet could be the genotypes and corresponding phenotypes of her parents? b. if e girl has blood type b end her mother has blood type a, what genotype(s) and corresponding phenotype(s) could the other parent have? c. if a girl has blood type aa and her mother is also ab, what ere the genotype(s) end corresponding phenotype(s) of any male who could not be her father?

a) OO/OO (phenotype O) ; OA (ph A)/OB (ph B)  ; OO(phO)/ OA(ph A); OO(ph O)/OB (ph B).

b) OB (ph B) or BB (phB) or AB (ph AB).

c) OO(ph O)

Explanation:

a) Blood type 0 is recessive. This girls genotype is  OO.

Then, parents need to have at least one allele O each in their genotype. Possibilities genotypes and phenotypes (ph): OO/OO (phenotype O) ; OA (ph A)/OB (ph B)  ; OO(phO)/ OA(ph A); OO(ph O)/OB (ph B).

b) Blood type B is co-dominant with A. If the girl is B, it means her genotype can be OB or BB.

But we are told that  the mother has blood type A. Also co-dominant. This means the girls genotype cannot be BB.

If the girl is OB, it means she got the O allele from her mother.

The other parent then has to be responsible for the B allele. This means the father could have been OB (ph B) or BB (phB) or AB (ph AB).

c) If the girl is AB (I assume misspelling) and her mother ALSO is AB, then the father cannot be OO(phO). Because he has to give the allele A or B to the girl.  

Any other genotype is possible.

the genotypes would be 50% bb and 50% bb

the phenotypes would be 50% brown and 50% white. hope this : )

the answer would be 2, if crossing over doesn’t occur 2 out of 4 of the daughter cells will have that allele.

hope this : )