Acappuccino vending machine is designed to dispense an average of ? oz per cup. if the ounces per fill are normally distributed, with a standard deviation of 0.4 oz, what value should ? be set at so 6 oz cups will overflow only 2% of the time? 6.82 oz 5.18 oz 5.60 oz 6.00 oz

5.18oz.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Overflow only 2% of the time?

Value of when Z has a pvalue of 1-0.02 = 0.98. So X when Z = 2.055.

So the correct answer is:

5.18oz.

the answer is d

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v