In a coffee-cup calorimeter, 1 mol naoh and 1 mol hbr initially at 22.5 oc (celsius) are mixed in 100g of water to yield the following reaction: naoh + hbr → na+(aq) + br-(aq) + h2o(l) after mixing the temperature rises to 83 oc. calculate the change in enthalpy of this reaction. specific heat of the solution = 4.184 j/(g oc) state your answer in kj with 3 significant figures. don't forget to enter the unit behind the numerical answer. the molecular weight of naoh is 40.0 g/mol, and the molecular weight of hbr is 80.9 g/mol.
Answers: 3
Chemistry, 21.06.2019 18:20, datboyjulio21
Complete the table for ion charge based upon their losing or gaining electrons in the outer shell. (use the periodic table as necessary.) group most likely ionic charge # of valence electrons i +1 ii +2 iii +3 iv +4 or -4 v -3 vi -2 vii -1 viii 0
Answers: 2
In a coffee-cup calorimeter, 1 mol naoh and 1 mol hbr initially at 22.5 oc (celsius) are mixed in 10...
History, 07.06.2020 05:59
Mathematics, 07.06.2020 05:59
Mathematics, 07.06.2020 05:59
Mathematics, 07.06.2020 05:59
Mathematics, 07.06.2020 05:59
Mathematics, 07.06.2020 05:59