What volume of solution is prepared when 25.0 g of ethanol (C2H5OH) is added to enough water to make a 0.750 M ethanol solution?

0.724 L

Explanation:

Step 1: Given data

Mass of ethanol (solute): 25.0 g

Concentration of the solution: 0.750 M

Step 2: Calculate the moles corresponding to 25.0 g of ethanol

The molar mass of ethanol is 46.07 g/mol.

25.0 g × (1 mol/46.07 g) = 0.543 mol

Step 3: Calculate the volume of the solution

We will use the following expression.

M = moles of solute / liters of solution

liters of solution = moles of solute / M

liters of solution = 0.543 mol / (0.750 mol/L)

liters of solution = 0.724 L

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