Asample of ammonia gas at 65.5°c and 524 torr has a volume of 15.31 l. what is its volume when the temperature is –15.8°c and its pressure is 524 torr?

According to gases formula:

P1V1/T1 = P2V2/T2

when P1 is the initial pressure = 524 torr

V1 is the initial volume = 15.31 L

T1 is the initial temperature= 65.5 + 273= 338.5

P2 is the final pressure = 524 torr

T2 is the final temperature = -15.8 +273 = 257.2

by substitution:

 524*15.31 /338.5 = 524*V2/257.2

∴ V2 = 6095.6 / 524

         = 11.6 L

∴ the final Volume = 11.6