Codio python challenge (max. py)

we will pass in a list of numbers. your job is to find the largest number in that list and output its index, not the actual value.

tip: you will need to use a utility variable to store the maximum value and a decision to see if each number is bigger than the current maximum value encounted in previous iterations

import sys

numbers = sys. argv[1]. split(',')

numbers = [int(1) for i in numbers]

#enter code here

I hope this helps:

https://stackoverflow.com/questions/3989016/how-to-find-all-positions-of-the-maximum-value-in-a-list

maximum=numbers.index(max(numbers))      

print("Maximum is at index {}".format(maximum))

Input :

4,5,2,6,2,1

Output :

Maximum is at index 3

Explanation:

In the above program, first max() function is used to find the maximum number of the list which is an inbuilt method of python.

Then, the output of above is passed as an argument to property of a list i.e. index() which gives the index of the parameter passed in this property. Here the maximum number's index is returned by this property.

This output is stored in variable maximum and after that the index of largest number in that list is printed in next line.

hey there! :

mass = 5.75 g

volume = 7.5 cm³

therefore:

density = mass / volume

d = 5.75 / 7.5

d = 0.7 g/cm³

answer c

hope that !

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