Aconcession stand has crates of bottled water to sell at a sporting event. each crate holds 48 bottled waters and costs the concession stand $9.20. if the concession stand wants to make exactly $34.00 profit per crate of bottled water, how much should customers be charged for each bottled water, in dollars and cents?

Each bottle should be sold for $0.9 or 90 cents

Explanation:

Assume that the price of each bottle is x

Now, we know that one crate holds 48 bottles of water

This means that the total money gained from selling the bottles will be $48x

We also know that the crate costs the concession stand $9.2 and that the concession stand wants to make a profit of $34

The equation used to calculate the profit is:

Profit = selling price - cost price

In our problem, we have:

Profit = $34

Selling price = money gained from water bottles = 48x

Cost price = cost of crate = $9.2

Substitute with these values in the equation and solve for x as follows:

Profit = selling price - cost price

34 = 48x - 9.2

48x = 34 + 9.2

48x = 43.2

x = $0.9 which is equivalent to 90 cents

Based on the above:

To be able to make a profit of $34, each bottle of water should be sold for $0.9 or 90 cents

Hope this helps :)

they should be sold for 90¢

Step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15