For a recent year, 0.99 of the incarcerated population is adults and 0.07 of the incarcerated are adult females. If an incarcerated person is selected at random, find the probability that the person is a female given that the person is an adult.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

just took the test and my answers down below!

step-by-step explanation:

check the pic :