Eva Destruction twirls a stone attached to a string 2.0 meters long in a horizontal circle. At what speed must the stone move for its centripetal acceleration to be equal to the acceleration due to gravity (g)? I NEED HELP ASAP PL

The required velocity is  4.4 m/s.

The centripetal acceleration is given by the formula;

ac= v^2/r

v = linear speed

r = radius of the circular path

We are looking for the velocity at which ac = g = 9.8m/s^2

We already have the radius of the circular path as 2.0 meters

9.8 m/s^2 = v^2/2 m

v = √2(9.8)

v = 4.4 m/s

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4.43 m/s

Explanation:

The radius of circle is = 2m

Acceleration due to gravity is = 9.8 m/s²

To find the speed the stone move for its centripetal acceleration to be equal to the acceleration due to gravity will be;

a=v²/r   where a is acceleration due to gravity and r is radius of the circle

9.8 =v²/2

9.8 *2 = v²

19.62 = v²

√19.62 =v

4.43 m/s = v

answer: option c.

explanation:

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray